gerak parabola
22.14 | Author: rahmat
Gerak parabola
Asumsi pertama tidak ada gaya dengan arah horizontal
F_x=0
Hukum Newton maka
F_x=mx ̈
Karena F_x=0 maka

x ̈=0
x ̇=∫▒〖0 dt=C〗 ;C= B_1
x ̇=B_1
x(t)=∫▒〖B_1 dt〗
=B_1 t+B_2
Jika
x(0)=x_0 maka
x(0)=B_1.0+B_2=B_2
x_0=B_2
x ̇(0)=V_(x0 ) B_1=V_xo
=B_1 B_2= x_0
Jika tidak mengalami gesekan udara maka
{█(x ̈=0@( y) ̈=-g)┤


{█(x(t)=B_1 t+B_2@y(t)=-1/2 〖gt〗^2+D_1+D_1 )┤
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